![\sqrt[3]{\dfrac{-27}{125}} = -\sqrt[3]{\left(\dfrac{3}{5}\right)^{3}}=\dfrac{-3}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cdfrac%7B-27%7D%7B125%7D%7D%20%3D%20-%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%7B3%7D%7B5%7D%5Cright%29%5E%7B3%7D%7D%3D%5Cdfrac%7B-3%7D%7B5%7D)
The appropriate choice appears to be ...
B. -3/5
Oksuru k diyaf ramincok ani kasilm asiyla olusan bir refle kstir.
Pq
because they constant is the multiple of the last digit of each factor
If I am understanding this right, since the <em>c </em>is a variable, you'd have to solve the equation and have the variable in the and result.
the sqrt525^7 = 3359983566.19
So you'd have to simplify this and add the <em>c</em> to the end of it. Unless your work is fractions.
(I take Algebra II I should be more confident on this topic, this is just what makes the most sense)
Answer:
(3, 3 )
Step-by-step explanation:
Given the 2 equations
3x - y = 6 → (1)
6x + y = 21 → (2)
Adding the 2 equations term by term will eliminate y, that is
(6x + 3x) + (y - y) = (21 + 6), that is
9x = 27 (divide both sides by 9 )
x = 3
Substitute x = 3 into either (1) or (2) and solve for y
Using (2), then
(6 × 3) + y = 21
18 + y = 21 ( subtract 18 from both sides )
y = 3
Solution is (3, 3 )
