Question

Please help me. 4^(x+1)+2^(x+1)+2^x-1=0

Answer 1

Answer:

x = -2

Step-by-step explanation:

Answer 2

Answer:

• x = -2

Step-by-step explanation:

• $4^{x+1}+2^{x+1}+2^x-1=0$
• $4*2^{2x}+2*2^x+2^x-1=0$

• 2ˣ = t

• 4t² + 3t - 1 = 0
• 4t² + 4t - t - 1 = 0
• 4t(t + 1) - (t + 1) = 0
• (t + 1)(4t - 1) = 0
• t = -1 (discounted as 2ˣ can't be negative)
• t = 1/4

• 2ˣ = 1/4
• 2ˣ = 2⁻²
• x = -2