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3 years ago

What is the sum of the geometric series t=1

1 answer:

7 0

In order for an infinite geometric series to have a sum, the common ratio r must be between −1 and 1. ... To find the sum of an infinite geometric series having ratios with an absolute value less than one, use the formula, S=a11−r, where a1 is the first term and r is the common ratio.

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HI!! Please answer this!

bezimeni [28]

Answer:

41 ≤ x

x ≤ 45

Step-by-step explanation:

8 0

1 year ago

HELP Use either law of sines or law of cosine. Need help on this problem! show work please!

Marina86 [1]

Answer: x = 15.035677095729 approximately

Round this however you need to.

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Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

sin(Q)/PR = sin(R)/PQ

sin(Q)/13 = sin(85)/19

sin(Q) = 13*sin(85)/19

sin(Q) = 0.6816068987

Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

Q = 42.9693397461 ... or ... Q = 137.0306602539

These values are approximate.

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Now if Q = 42.9693397461 approximately, then angle P is

P = 180-Q-R

P = 180-42.9693397461-85

P = 52.0306602539

Similarly, if Q = 137.0306602539 approximately, then,

P = 180-Q-R

P = 180-137.0306602539-85

P = -42.0306602539

A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

sin(P)/p = sin(R)/r

sin(P)/QR = sin(R)/PQ

sin(52.0306602539)/x = sin(85)/19

19*sin(52.0306602539) = x*sin(85)

19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

This value is approximate.

Round this value however you need to.

4 0

2 years ago

Read 2 more answers

Angle XYZ is rotated 270 degrees counterclockwise about the origin to form angle X’Y’Z’. Which statement shows the measure of an

Kruka [31]

Hi i a doing the same thing and i have the answer as a hope this helps

6 0

2 years ago

Question in pic. please help!

bonufazy [111]

Answer: 1, 3, and 4 can form triangles. The rest can not.

Step-by-step explanation:

on triangles 1, 3, and 4, the 2 smaller sides added together are greater than the longer side.

4 0

2 years ago

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Find the area of the following circles. a. A circle with a 8-inch radius b. A circle with a 10-kilometer radius c. A circle with

Thepotemich [5.8K]

Area of a circle is $A= \pi r^2$ . The first one, a, the radius squared is 8*8=64. So $A=64 \pi$ . If you multiply in pi as 3.14, you'll have 200.96 square inches. The second one, b, the radius squared is 10*10=100. So $A=100 \pi$ square kilometers. If you multiply in pi as 3.14 you'll have 314 square kilometers. The third one, c, the radius squared is 14*14=196. So $A=196 \pi yd^2$ . Or you could multiply in pi as 3.14 to get 615.44 yd squared. For the last one, d, the radius squared is 22*22=484 cm. Therefore, $A=484 \pi cm^2$ , or multiply in 3.14 for pi to get 1519.76 cm squared. There you go!

5 0

2 years ago

Read 2 more answers