The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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You would use the function root(Xsub2-Xsub1)^2+(Ysub2-Ysub1)^2.
Now plug in your numbers.
This gives you root(7-1)^2+(5-(-3))^2.
Simplify to root(6)^2+(8)^2. Simplify again to root36+64.
Simplify one more time to root 100. now solve.
Your answer is 10.
Answer:
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Step-by-step explanation:
Answer:
F=1
Step-by-step explanation:
8=8x1
