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3 years ago

How do you find h(x)?

Mathematics

1 answer:

dusya [7]3 years ago

4 0

First what are the instructions up above on your page?

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Emmanuel has 745 pictures in his phone his memory is getting full so he starts deleting 20 pictures everyday if I need to be abl

Lelechka [254]

PhotosRemaining(x) = 745 pictures - (20 pictures/day)*(x), for x≥0

3 0

3 years ago

Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters

Mumz [18]

The various answers to the question are:

To answer 90% of calls instantly, the organization needs four extension lines.
The average number of extension lines that will be busy is Four
For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

<h3>How many extension lines should be used if the company wants to handle 90% of the calls immediately?</h3>

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

$P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$$

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$$

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$$

Generally, the equation for is mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

The probability that a call will receive a busy signal if four extensions lines are used is,

$P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$$

Therefore, the average number of extension lines that will be busy is Four

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

$P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$$

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

Read more about extension lines

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8 0

2 years ago

For what value of "x" will the expression -3*5*x have a positive answer"

balu736 [363]

The value of that expression is positive whenever 'x' is negative.

3 0

3 years ago

What is the slope of find the slope of the line described by 4x + 5y = 60?

JulsSmile [24]

1) isolate y

4x + 5y = 60
-4x -4x
_____________
5y = -4x + 60

2) make y so that is is alone with no numbers beside it

5y = -4x + 60
__________
5

y = -4/5x + 60

3) the slope is ALWAYS the number to the left of x, even if it's a fraction. It's it a decimal, convert to a fraction. The last number (in this case is 60) is where the slope crosses the y-axis on the coordinate plane.

The slope is -4/5x + 60

5 0

3 years ago

Dos personas A y B , se encuentran en la orilla de un río, separadas entre sí 200 m y en la orilla opuesta en el punto C, se enc

Kryger [21]

Answer:

La distancia de C con respecto a A es de 197.788 metros.

Step-by-step explanation:

A manera de imagen adjunta construimos una representación del enunciado del problema, la cual representa a un triángulo cuyos tres ángulos son conocidos y la longitud del segmento AB, medida en metros, son conocidos. Por medio de la Ley del Seno podemos calcular la longitud del segmento AC (distancia de C con respecto a A), medida en metros:

$\frac{AB}{\sin C} = \frac{AC}{\sin B}$ (1)