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Ira Lisetskai [31]

3 years ago

9

Find the difference x/25x-125-1/x^2-5x

1 answer:

lozanna [386]3 years ago

4 0

The difference of <span> x/25x-125-1/x^2-5x

</span> (x/25x-125)-1/(x^2-5x)= x / 25(x-5) - 1/ x(x-5) = (1/x-5)(x/25-1/x) factorized by 1/x-5, and (1/x-5)(x/25-1/x) = (1/x-5)(x²-25/25x)= <span>(1/x-5) [(x-5)(x+5) / 25x]
</span>= (x+5) / <span>25x simplified by x-5
</span><span>so the final answer is
</span> x/25x-125-1/x^2-5x = (x+5) / <span>25x</span>

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