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2 years ago

The expanded form of the whole number 470,052 is

Mathematics

1 answer:

Contact [7]2 years ago

5 0

The answer would be 400,000; 70,000; 50; 2.
Hope this helps!

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The school band is ordering health bars to sell for a fundraiser. The company that sells the bars charges $0.40 per bar plus $20

Pepsi [2]

Answer: They can order from 0 to 449 bars, but no more.

Step-by-step explanation:

Given: The school band is ordering health bars to sell for a fundraiser. The company that sells the bars charges $0.40 per bar plus $20.00 for shipping regardless of the size of the order. The band must spend less than $200.00 on bars for the fundraiser.

The inequality below relates x, the number of bars that could be ordered, with the shipping costs and their spending requirements.

$0.40x+20$

To solve for x, subtract 20 on both sides, we get

$0.40x$

Divide 0.40 on both sides, we get

$x$ ......... → the number of bars that could be ordered, with the shipping costs and their spending requirements must less than 450.

Thus, they can order from 0 to 449 bars, but no more.

4 0

3 years ago

Read 2 more answers

A circle has a circumference of 1,017,36 units.<br> What is the radius of the circle?

Bess [88]

Answer:

161.92 is the radius

If you want, you can round it to 162 units

7 0

2 years ago

7x - 2 = 2y

ser-zykov [4K]

$\left\{\begin{array}{ccc}7x-2=2y\\3x=2y-1\end{array}\right\\\\substitution:\\\\3x=7x-2-1\\3x-7x=-3\\-4x=-3\ \ \ /:(-4)\\x=\frac{3}{4}\\\\2y=7\cdot\frac{3}{4}-2=\frac{21}{4}-2=\frac{21}{4}-\frac{8}{4}=\frac{13}{4}\\2y=\frac{13}{4}\ \ \ \ /:2\\y=\frac{13}{8}\\\\Answer:x=\frac{3}{4};\ y=\frac{13}{8}.$

6 0

2 years ago

Find the x in the given triangle and at last do the proof...please help

viva [34]

Answer:

x = 42.67

Step-by-step explanation:

5 0

2 years ago

Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex

siniylev [52]

Answer:

$\large \boxed{\sf \ \ \ p=-11 \ \ \ }$

Step-by-step explanation:

Hello,

$\alpha \text{ and } \beta \text{ are the roots of the following equation}$

$2x^2+6x-7=p$

It means that

$2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\$

And we know that

$\alpha= 2\cdot \beta$

So we got two equations

$2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1$