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2 years ago

The expanded form of the whole number 470,052 is

Mathematics

1 answer:

Contact [7]2 years ago

5 0

The answer would be 400,000; 70,000; 50; 2.
Hope this helps!

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A storage tank has A circumference Of 200 meters what is the area of the base of the tank

lorasvet [3.4K]

Circumference = 2 pi r

2 pi r = 200

r = 100 / pi

Area of base = pi r r

Area of base = 100*100 / pi

Area of base = 3183.1 sq. m.

6 0

3 years ago

Sadie finished her math test in sixteen minutes less than three times the amount of times it took her friend Laura to finish.if

amid [387]

Answer:

Sadie took 47 minutes to finish her test.

Step-by-step explanation:

Let Laura's time be x minutes.

Then we have:

x + 3x - 16 = 68

4x = 84

x = 21 minutes.

So Sadie took 3(21) - 16 = 63-16

= 47 minutes.

3 0

3 years ago

Can someone please help !!!

Vera_Pavlovna [14]

Answer:

A = 6.3033315211545 in2 or 6.3

Step-by-step explanation:

7 0

3 years ago

Simplify the exponential expression. ( 1/5 ) 2 =

Ierofanga [76]

Answer:

Fraction form- 2/5

Decimal form- 0.4

Step-by-step explanation:

Distribute.

Have a good day!

7 0

3 years ago

Read 2 more answers

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago