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MissTica
3 years ago
12

Really need help...

Mathematics
1 answer:
Andre45 [30]3 years ago
4 0
Sinθ = 16/20 = 0.8 
θ = arcsin(0.8) ≅ 53° 
::::: 
Use ^2 to represent ². 
Pythagorean identity: 
sin²(x) + cos²(x) = 1
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Whats the slope form?
katen-ka-za [31]
The answer is in slope form : Y=1x+5

Reason: all you do is (rise/run) to get the slope. So take (5/5)=1x (slope). Also, your intercept is +5.

8 0
3 years ago
The base and height of a right triangle are 20 inches and 15 inches. Find the length of the hypotenuse.
Karolina [17]

Using the Pythagorean theorem:

Hypotenuse = sqrt( 20^2 + 15^2)

Hypotenuse = sqrt( 400 + 225)

Hypotenuse = sqrt(625)

Hypotenuse = 25

Answer: 25 inches

8 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept form for this line. A line passes through the point (10,-7) and has a slope of -5/2
Damm [24]

y =  -  \frac{5}{2} x + 18
i think
6 0
3 years ago
Sid brought $200 to the amusement park . the cost of admission is $16.25 , and the cost of a lunch is $6.50 . After Sid purchase
ra1l [238]
Let x represent the # of people in sid’s group: 200 - (16.25x + 6.50x) = 18.25
200 - 22.75x = 18.25
-22.75x = -181.75
x = about 8

if Sid is not included in the group, i think the answer is D. 7, but im not sure
5 0
3 years ago
HELP ASAP!!! 40 POINTS
ICE Princess25 [194]

Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:

(-15,-10).

<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>

It is given by the derivative at x = x0, that is:

m = f^{\prime}(x_0).

In this problem, the function is:

f(x) = 0.2x^2 + 5x - 12

Hence the derivative is:

f^{\prime}(x) = 0.4x + 5

For a slope of -1, we have that:

0.4x + 5 = -1

0.4x = -6

x = -15.

For a slope of 1, we have that:

0.4x + 5 = 1.

0.4x = -4

x = -10

Hence the interval is:

(-15,-10).

More can be learned about derivatives and tangent lines at brainly.com/question/8174665

#SPJ1

8 0
2 years ago
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