For the values 36 and 45, the GCF = 9
The standard form of the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle, (x,y) is a point of the circle, and r is the length of the radius of the circle. When the equation of a circle is written, h,k, and r are numbers, while x and y are still variables. (x-2)^2 + (y-k)^2 = 16 is an example of a circle. The problem gives us two of the three things that a circle has, a point (5,9) and the center (-2,3). We need to find the radius in order to write the equation. We substitute -2 for h, 3 for k, 5 for x, and 9 for y to get (5 - (-2))^2 + (9 - 3)^2 = r^2 We simplify: 49 + 36 = r^2, r^2 = 85. We only need to know r^2 because the equation of a circle has r^2. We now have all the information to write the equation of a circle. (x + 2)^2 + (y - 3)^2 = 85.
Answer:
happy birth day to me
Step-by-step explanation:
its F was i close
Answer:
x=11
Step-by-step explanation:
5x+13=9x-31
subtract 9 from both sides.
-4x+13=-31
you want to isolate the x value so subtract 13 from both sides.
-4x=-44
now divide both sides by -4.
x=11
Answer:
None of them are correct because the circumference formula is 2pir