What is -3/8 divided by -6/7? Help quick please

Mathematics

2 answers:

olganol [36]3 years ago

8 0

Namaste :)

HERE IS YOUR ANSWER:

SEE THE ATTACHMEMT

True [87]3 years ago

4 0

The fraction is 7/16 and the decimal version is 0.4375

You might be interested in

A restaurant earns $1073 on Friday and $1108 on Saturday. Write and solve an equation to find the amount x (in dollars) the rest

Rzqust [24]

The answer is 1073+1108+819 all of this divided by 3 equals 1000, here's a picture of my board to see how I'vé done it

6 0

3 years ago

The amount of money in Toni's savings account after x weeks is described by the function f(x) = 5x + 20. Which best interprets t

musickatia [10]

Answer:

Toni's account started with 20 and increased by 5 each week.

Step-by-step explanation:

20 is the intial amount and 5 is the rate of change.

7 0

4 years ago

A certain change in a process for manufacture of component parts is being considered. Samples are taken using both the existing

Katyanochek1 [597]

Answer:

a) The confidence interval is $0.00\leq\pi_1-\pi_2\leq0.02$ .

Step-by-step explanation:

We have to calculate a confidence interval (CI) of a difference of proportions.

For the existing procedure, the proportion is:

$p_1=75/1500=0.05$

For the new procedure, the proportion is:

$p_2=80/2000=0.04$

To calculate the CI, we need to estimate the standard deviation

$s=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2} }\\\\s=\sqrt{\frac{0.05(1-0.05)}{1500} +\frac{0.04(1-0.04)}{2000} }=\sqrt{ 0.000032 + 0.000019 }=\sqrt{ 0.000051 }\\\\s=0.007$

For a 90% CI, the z-value is 1.64.

Then, the CI is:

$(p_1-p_2)-z*\sigma \leq\pi_1-\pi_2\leq(p_1-p_2)+z*\sigma \\\\(0.05-0.04)-1.64*0.007\leq\pi_1-\pi_2\leq(0.05-0.04)+1.64*0.007\\\\0.01-0.01\leq\pi_1-\pi_2\leq0.01+0.01\\\\0.00\leq\pi_1-\pi_2\leq0.02$