Answer:
1. x^2 − 4x + 3 = 0
So we have two real solutions
2. 2n^2 + 7 = −4n + 5
So we just one real solution
3. x − 3x^2 = 5 + 2x − x^2
No real solutions
4. 4x + 7 = x^2 − 5x + 1
So we have two real solutions
Step-by-step explanation:
1. x^2 − 4x + 3 = 0
We need to compare this function with the general equation for a quadratic formula given by:
On this case we see that a=1, b = -4 and c =3
We can find the discriminat with the following formula:
So we have two real solutions
2. 2n^2 + 7 = −4n + 5
We can rewrite the expression like this:
On this case we see that a=2, b = 4 and c =2
We can find the discriminat with the following formula:
So we just one real solution
3. x − 3x^2 = 5 + 2x − x^2
We can rewrite the expression like this:
On this case we see that a=2, b = 1 and c =5
We can find the discriminat with the following formula:
No real solutions
4. 4x + 7 = x^2 − 5x + 1
We can rewrite the expression like this:
On this case we see that a=1, b = -9 and c =-6
We can find the discriminat with the following formula:
So we have two real solutions