3 years ago

1.

Mathematics

1 answer:

SashulF [63]3 years ago

6 0

Let $2n+1$ be the first integer. Then the next three odd integers are $2n+3,2n+5,2n+7$

The sum of the second and third integers is 19 greater than the fourth, so that

$(2n+3)+(2n+5)=19+(2n+7)\implies2n=18\implies n=9$

Then the first integer is 19, and the four integers in question are 19, 21, 23, and 25.

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