Question

1.

Answer 1

Let $2n+1$ be the first integer. Then the next three odd integers are $2n+3,2n+5,2n+7$

The sum of the second and third integers is 19 greater than the fourth, so that

$(2n+3)+(2n+5)=19+(2n+7)\implies2n=18\implies n=9$

Then the first integer is 19, and the four integers in question are 19, 21, 23, and 25.