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3 years ago

Recognize and write symbols for perpedicular and parallel lines 4th grade

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

5 0

| | parallel

an upside-down T is the symbol for perpendicular

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If it takes 1074 digits to number the pages of a book starting with page 1. how many pages are in the book? The book has a total

Charra [1.4K]

Answer:

394 pages

Step-by-step explanation:

<u>1- digit numbers: </u>

1 to 9, number of digits = 9

<u>2- digit numbers:</u>

10 to 99, number of digits = 2(99 - 9) = 180

<u>3- digit numbers:</u>

100 to 999, number of digits = 3(999 - 99) = 2700

This is more than we have, but we know the number of pages is 3-digit.

9 + 180 + 3(x - 99) = 1074
3(x - 99) = 1074 - 189
3(x - 99) = 885
x - 99 = 885/3
x - 99 = 295
x = 295 + 99
x = 394

4 0

3 years ago

Why is 1 neither prime nor a composite number?

Nadya [2.5K]

Answer:

1 is neither prime nor a composite number because it only has 1 divisor, 1 and 1, and it doesn't have more than 2 integral divisors, like stated, it only has 1. So it falls in neither category.

7 0

2 years ago

Read 2 more answers

What is 79 881/1000 as decimal

den301095 [7]

79.881 hope this helps
i might be wrong

6 0

4 years ago

What the answer to this problem

g100num [7]

The equation:

$(x-10)+40+(x-20)+3x=360\\\\(x+x+3x)+(-10+40-20)=360\\\\5x+10=360\ \ \ \ |-10\\\\5x=350\ \ \ \ |:5\\\\x=70$

8 0

3 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago