Because n > 30, the sampling distribution of the mean ages can be approximated by a normal distribution with mean µ and standard deviation σ ÷ √(45) .The central limit theory applies whenever n > 30. Because n > 30, the sampling distribution of the mean ages can be approximated by a normal distribution with mean µ and standard deviation σ ÷ √(n) .

5 0

3 years ago

.prove that cos (90-A).sinA + sin(90 - A).cosA = 1

pav-90 [236]

Answer:

See Explanation

Step-by-step explanation:

$cos (90-A).sinA + sin(90 - A).cosA = 1 \\ \\ LHS = cos (90-A).sinA + sin(90 - A).cosA \\ \\ = sinA.sinA + cosA.cosA\\ \\ = sin ^{2} A + cos^{2} A \\ \\ = 1 \\ \\=RHS\\\\ reason \\ cos (90- \theta) = sin \theta \\ sin (90- \theta) = cos \theta \\ sin ^{2} \theta + cos^{2} \theta = 1 \\ \\ thus \: proved \\$

4 0

3 years ago

What is the answer to this sum 5/6 of 120

ELEN [110]

100 is the correct answer

6 0

3 years ago