Answer:
Step-by-step explanation
Hello!
Be X: SAT scores of students attending college.
The population mean is μ= 1150 and the standard deviation σ= 150
The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.
If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:
H₀: μ = 1150
H₁: μ ≠ 1150
α: 0.05
![Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)](https://tex.z-dn.net/?f=Z%3D%20%5Cfrac%7BX%5Bbar%5D-Mu%7D%7B%5Cfrac%7BSigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20~~N%280%3B1%29)

The p-value for this test is 0.0949
Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.
I hope it helps!
Answer:
x = 52 i hope this helps! :)
Step-by-step explanation:
so first you gotta realize that every triangle has an interior angle measurement sum of 180 degrees
so we are given 3 angles 74 degrees x + 2 and x
we now are going to put this into an equation 74 + x + 2 + x = 180
now lets combine like terms to get 76 + 2x = 180
then we are going to subtract the 76 from both sides 2x = 104
now lets divide both sides by 2 x = 52
so x = 52
we can plug in the value of x into both of the other equations to find the angle measurement
52 degrees
52 + 2 = 54 degrees
and then we have 74 degrees
add the 52, 54, and the 74 to make sure it is equal to 180 degrees
106 + 74 = 180
so yes, x does indeed equal 52 degrees
El tenia $325
$250+$75=$325
Espero q te ayude :)