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Rudik [331]
3 years ago
7

What is the length of BC, rounded to the nearest tenth?

Mathematics
2 answers:
Norma-Jean [14]3 years ago
4 0

Answer:

Option C. BC=31.2\ units

Step-by-step explanation:

step 1

In the right triangle ABD find the length side AB

Applying the Pythagoras Theorem

AB^{2}=5^{2}+12^{2}

AB^{2}=169

AB=13\ units

step 2

In the right triangle ABD

we know that

m

sin( -------> equation A

step 3

In the right triangle ABC

sin( ------> equation B

Remember that

m

so equate equation A and equation B solve for DC

\frac{5}{13}=\frac{13}{5+DC}

5(5+DC)=13*13

25+5DC=169

5DC=169-25

5DC=144

DC=144/5=28.8\ units

step 4

In the right triangle BDC find the length side BC

Applying the Pythagoras Theorem

BC^{2}=28.8^{2}+12^{2}

BC^{2}=973.44

BC=31.2\ units

Alik [6]3 years ago
3 0
The answer is C.31.2 HOPE IT HELPS
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