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Delicious77 [7]
4 years ago
6

The art club spent $45 on supplies for valentines to sell during lunches. They made 60 valentines. What selling price for a vale

ntine would result in a profit of zero if all the valentines are sold?
Mathematics
1 answer:
RUDIKE [14]4 years ago
7 0
60/45 = $0.75
It costs $0.75 to make each valentine so if they were sold for 75 cents then that would result in a profit of zero if all the valentines were sold. 
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If a mole of sodium chloride weighs approximately 58 grams, and you have 29 grams of sodium chloride, how many moles of sodium c
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The answer is <span>A.0.5 moles 

</span><span>a mole of sodium chloride weighs approximately 58 grams: 1 M - 58 g
</span><span>you have 29 grams of sodium chloride, how many moles of sodium chloride do you have: xM - 29g

1 M : 58g = x : 29 g
x = 1 M : 58g * 29 g = 0.5 M</span>
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Answer:

The price of hot dog is $2.5 and that of a pretzel is $1.25.

Step-by-step explanation:

Let the cost of hotdogs be x and that of pretzels be x.

So,

4x+3y = 13.75 ...(1)

and

2x+5y = 11.25 ...(2)

Multiply equation (2) by 2.

4x+10y = 22.5 ...(3)

Subtract equation (1) from (3).

4x+10y-(4x+3y) = 22.5-13.75

4x+10y-4x-3y = 8.75

7y = 8.75

y = 1.25

Put the value of y in equation (1).

4x+3(1.25) = 13.75

4x+3.75 = 13.75

4x = 13.75-3.75

4x = 10

x = 2.5

So, the price of hot dog is $2.5 and that of a pretzel is $1.25.

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