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Tatiana [17]
3 years ago
6

Need help with this problem!! Point X is the midpoint of HI. What is the coordinate of the point X?

Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

Answer:

1

Step-by-step explanation:

The midpoint is the average of the points H and I

midpoint = | \frac{-2+4}{2} | = | \frac{2}{2} | = | 1 | = 1

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Brainly which is the distance between (-3,4) and (7,13)
Veseljchak [2.6K]

Answer:

Root 181

Step-by-step explanation:

         Using distance formula, we know that the answer will be the square root of 181. Unfortunately, this is not a perfect square, and it is prime, so that number will remain the same.

Distance Formula: \sqrt{(13-4)^{2} + (7+3})^2} = \sqrt{181}

Hope this helped!

5 0
3 years ago
Inverse of f(x)=3x-4
aniked [119]

Answer:

\large\boxed{f^{-1}(x)=\dfrac{x+4}{3}=\dfrac{1}{3}x+\dfrac{4}{3}}

Step-by-step explanation:

f(x)=3x-4\to y=3x-4\\\\\text{exchange x to y and vice versa}\\\\x=3y-4\\\\\text{solve for y}\\\\3y-4=x\qquad\text{add 4 to both sides}\\\\3y=x+4\qquad\text{divide both sides by 3}\\\\y=\dfrac{x+4}{3}

8 0
3 years ago
How much heat is released when 12. 0 grams of helium gas condense at 2. 17 K? The latent heat of vaporization of helium is 21 J/
aleksandr82 [10.1K]

The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J

The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.

However, since we are required to determine heat released when the helium gas condenses.

The heat of condensation per gram is; -21 J/g.

Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.

Approximately, -250J.

Read more on latent heat:

brainly.com/question/19863536

7 0
2 years ago
The side lengths of a triangle are 9, 12, and 15. Is this a right triangle?
Ierofanga [76]

Answer:

Step-by-step explanation:

Those are the side lengths not the angles so I'm not sure, also are you sure that's right? I believe there has to be a hypotenuse and the hypotenuse is the sum of the two shorter sides added together.

Do you have any more information? I can try to help :)

5 0
3 years ago
Read 2 more answers
What is the area of the sector ?​
worty [1.4K]

They forget to say "not to scale".  I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first.  By the Law of Cosines

x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ

We have an isosceles triangle formed by two radii of 9 cm and x=PQ.  By the Law of Cosines again,

x^2 = 9^2 + 9^2 - 2(9)(9) \cos B

x^2 = 162 - 162 \cos B

\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}

\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}

B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)

The area of the circle is the fraction given by the angle,

A = \dfrac{B}{360^\circ} \pi r ^2

A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2

A\approx 24.7474332960707

Answer: 24.7 sq cm

8 0
3 years ago
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