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salantis [7]
2 years ago
8

How do i conjugate the binomial

qrt{6 + 4} " alt=" \sqrt{6 + 4} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
leonid [27]2 years ago
3 0
We solve 6 + 4

6 + 4 = 10.

Square root of 10:

\boldsymbol { \sqrt{6 + 4} =  \sqrt{10}  }\\
\\
\\
\boldsymbol {  \sqrt{10}l\underline{ \ 3.16227766017}}\\
\boldsymbol {  \underline{- 10}l \ 3.16227766017 \times 3.16227766017 }\\
\boldsymbol { \ \ \ 00}

<span>The square root of 10 is a periodic decimal (decimal that has infinite decimals, worth the redundancy)

 What is that periodic decimal?
</span>
\boxed{\textbf{3.16227766017} \boldsymbol{ \ \Leftarrow }\textbf{Square root of 10}}

<u>REGARDS!</u>
You might be interested in
A town has two trucks to collect garbage. When both truck are in use, they take 6 hours to collect all the garbage. When only th
jeka94

Answer:

8 hours

Step-by-step explanation:

In this case, the speed would be given by the garbage collection / hour, therefore the two together, that is to say from the sum of both, would be 1/6 the speed and for the small truck it would be 1/24

So to calculate the speed of the big truck it would be:

1/24 + 1 / x = 1/6

1 / x = 1/6 - 1/24

1 / x = 0.125

x = 1 / 0.125

x = 8

Which means that only the big truck would take only 8 hours

4 0
3 years ago
The radius of a sphere is increasing at a rate of 3 mm/s. How fast is the volume increasing when the diameter is 60 mm
mina [271]

Answer:

The volume is increasing at a rate of 33929.3 cubic millimeters per second.

Step-by-step explanation:

Volume of a sphere:

The volume of a sphere of radius r is given by:

V = \frac{4\pi r^3}{3}

In this question:

We have to derivate V and r implicitly in function of time, so:

\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}

The radius of a sphere is increasing at a rate of 3 mm/s.

This means that \frac{dr}{dt} = 3

How fast is the volume increasing when the diameter is 60 mm?

Radius is half the diameter, so r = 30. We have to find \frac{dV}{dt}. So

\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}

\frac{dV}{dt} = 4\pi (30)^2(3) = 33929.3

The volume is increasing at a rate of 33929.3 cubic millimeters per second.

5 0
2 years ago
When One Route and their support act, Cinnamon Bunnies, played, £54,000 was split at a ratio of 1:3:8 between the arena, Cinammo
dimaraw [331]

The ratio is split as arena first, Cinnamon Bunnies second and One Route third.

Add the ratios together: 1 + 3 +8 = 12

Divide the total money by 12, then multiply that by the share One Route gets (8)

54,000 / 12 = 4,500

4,500 x 8 = 36,000

One Route get £36,000

3 0
2 years ago
Read 2 more answers
Birds arrive at a birdfeeder according to a Poisson process at a rate of six per hour.
m_a_m_a [10]

Answer:

a) time=10 \frac{1}{6}=\frac{10}{6}=1.67 hours

b) P(T\geq 0.25h)=e^{-(6)0.25}=0.22313

c) P(T\leq 0.0833)=1-e^{-(6)0.0833}=0.39347

Step-by-step explanation:

Definitions and concepts

The Poisson process is useful when we want to analyze the probability of ocurrence of an event in a time specified. The probability distribution for a random variable X following the Poisson distribution is given by:

P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}

And the parameter \lambda represent the average ocurrence rate per unit of time.

The exponential distribution is useful when we want to describ the waiting time between Poisson occurrences. If we assume that the random variable T represent the waiting time btween two consecutive event, we can define the probability that 0 events occurs between the start and a time t, like this:

P(T>t)= e^{-\lambda t}

a. What is the expected time you would have to wait to see ten birds arrive?

The original rate for the Poisson process is given by the problem "rate of six per hour" and on this case since we want the expected waiting time for 10 birds we have this:

time=10 \frac{1}{6}=\frac{10}{6}=1.67 hours

b. What is the probability that the elapsed time between the second and third birds exceeds fifteen minutes?

Assuming that the time between the arrival of two birds consecutive follows th exponential distribution and we need that this time exceeds fifteen minutes. If we convert the 15 minutes to hours we have 15(1/60)=0.25 hours. And we want to find this probability:

P(T\geq 0.25h)

And we can use the result obtained from the definitions and we have this:

P(T\geq 0.25h)=e^{-(6)0.25}=0.22313

c. If you have already waited five minutes for the first bird to arrive, what is the probability that the bird will arrive within the next five minutes?

First we need to convert the 5 minutes to hours and we got 5(1/60)=0.0833h. And on this case we want a conditional probability. And for this case is good to remember the "Markovian property of the Exponential distribution", given by :

P(T \leq a +t |T>t)=P(T\leq a)

Since we have a waiting time for the first bird of 5 min = 0.0833h and we want that the next bird will arrive within 5 minutes=0.0833h, we can express on this way the probability of interest:

P(T\leq 0.0833+0.0833| T>0.0833)

P(T\leq 0.1667| T>0.0833)

And using the Markovian property we have this:

P(T\leq 0.0833)=1-e^{-(6)0.0833}=0.39347

3 0
3 years ago
Convert 18532.6 into scientific notation
balandron [24]
Here's what you need to do:

Well, you can't there's no zeros so this will be the answer

18532.6×10^0=

That would be your answer.
7 0
3 years ago
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