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Luba_88 [7]
3 years ago
5

Choose the definition for the function.

Mathematics
1 answer:
Rufina [12.5K]3 years ago
4 0

Answer:

Step-by-step explanation:

{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1

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Step-by-step explanation:

The area of a rectangle is A = W*L

where L is the width and L is the lenght.

Now, the original rectangle has a measure of 8 in by 6 in.

if 8in is the lenght and 6 in is the width.

We want to divide only one of those measures in equal parts, such that when we take the product of the end results is equal to 24 in.

If we divide the lenght by half (so both parts will have the same width as this did not change), we now have that the lenght is 8in/2 = 4in and the width is 6in.

Now the area is 4in*6in = 24in, which is the area that we where looking for.

We also could cut the width in half, and get the dimensions 8 inches by 3 inches.

5 0
3 years ago
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7 0
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Continue the number pattern/sequence:
Yuki888 [10]


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3 years ago
Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match the system of equations with their so
allochka39001 [22]

Answer:

Part 1) solution {(-5,8),(3,0)} ----> y+12=x^{2}+x and x+y=3

Part 2) No solutions ----> y-15=x^{2}+4x and x-y=1

Part 3) solution [(-2,5),(3,-5)] ---> y+5=x^{2}-3x and 2x+y=1

Part 4) No solutions ---> y-6=x^{2}-3x and x+2y=2

Part 5) solution [(2,3),(8,9)] --->y-17=x^{2}-9x and -x+y=1

Part 6) solution [(-2,3),(7,-6)] --->y-15=-x^{2}+4x and x+y=1

Step-by-step explanation:

Part 1) we have

y+12=x^{2}+x ----> equation A

x+y=3 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-5,8) and (3,0)  

see the attached figure N 1

Part 2) we have

y-15=x^{2}+4x ----> equation A

x-y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs  

see the attached figure N 2

Part 3) we have

y+5=x^{2}-3x ----> equation A

2x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,5) and (3,-5)  

see the attached figure N 3

Part 4) we have

y-6=x^{2}-3x ----> equation A

x+2y=2 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs    

see the attached figure N 4

Part 5) we have

y-17=x^{2}-9x ----> equation A

-x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (2,3) and (8,9)  

see the attached figure N 5

Part 6) we have

y-15=-x^{2}+4x ----> equation A

x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,3) and (7,-6)  

see the attached figure N 6

5 0
3 years ago
I'll give brainlisest and thanks, picture below!!
tester [92]

Answer:

Your answer is A. good luck

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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