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USPshnik [31]
3 years ago
13

Josh kept 75% of the ride tickets he bought at a carnival and gave the rest to his friend Sam. Sam gave 50% of these tickets to

Rob. If Rob was given 3 tickets, how many tickets did Josh buy?

Mathematics
1 answer:
galina1969 [7]3 years ago
7 0
Do percent over 100 and then cross multiply and you should receive your answer.
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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B36%7D%7B169%7D%7D" id="TexFormula1" title="\sqrt{\frac{36}{169}}" alt="\sq
otez555 [7]

Answer:

0.0355029585799?

Step-by-step explanation:

5 0
3 years ago
Pls answer this and I will mark it as brainlisti
Anna11 [10]

Answer:$2175

Step-by-step explanation:

set up an equation

15x+675

15(100) +675= 2175

15 is the additional cost per person

675 is the renting fee for the building

100 is the number of people attending

Hope this helps

5 0
3 years ago
Read 2 more answers
Hello please help i’ll give brainliest
salantis [7]

Answer:

"The dog" doesn't belong in the sentence

5 0
2 years ago
Me podrían ayudar y explicarme el proceso please
kakasveta [241]

Answer: Encontrarás las respuestas debajo de cada explicación. Espero que consideres darme brainliest y 5 estrellas, y más importante, que hayas entendido.

Step-by-step explanation:

Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

1 - 20kg

ahora queremos saber cuantas cajas (x) equivalen a 7653kg

x - 7653kg

Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

Pongamos la cantidad de cajas en la izquierda y el peso en la derecha

\frac{1}{x} =\frac{20kg}{7653kg}

Procedemos a multiplicar en cruz. Solo podemos multiplicar si tenemos ambos valores. En este caso, los valores en cruz que tenemos son 1 y 7653kg porque en la otra cruz (20 y x) tenemos nuestra incognita. Y, por ultimo, dividimos entre el numero cuya cruz es con la incognita (20kg)

Esto nos deja la expresión así;

x=\frac{1*7653kg}{20kg}

x=382.65

Como una caja no puede ser un numero decimal, redondeamos.

x=383

Por lo tanto, se necesitan aproximadamente 383 cajas para que su peso equivalga a 7653 kg.

-------------------------------------------------------------------------------------------------------

La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

\frac{1}{x}=\frac{20kg}{9500kg}

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

x=\frac{1*9500kg}{20kg}

x=475

Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

--------------------------------------------------------------------------------------------------------

Por último, la pregunta dice, ¿Cuántos kilogramos hay en 873 cajas?

Ya sabemos que una caja pesa 20kg ( 1 - 20kg ) y ahora buscamos cuantos kg hay en 873 cajas; es decir, (873 - x)

Nos quedaría así;

\frac{1}{873}=\frac{20kg}{x}

Ahora, nuestra cruz es 873 y 20kg, y el divisor es 1.

x=\frac{873*20kg}{1}

x=17460kg

Este sería el peso de 873 cajas.

5 0
3 years ago
Complete the equation of the line through (−8,8), and (1,-10 ). Use exact numbers. Help me please my dog just died and I want to
katrin2010 [14]

Answer: (Mayadc821 wrote this anwser check theyre account for more)

Since you know the x and y values, you just have to plug these into the linear slope-intercept equation:

y = mx + b

-10 = m(1) + b

m + b = -10

b = -10 - m

Now that we have a value for b, we can plug this into the other equation:

8 = m(-8) + b

8 = -8m + (-10 - m)

8 = -9m -10

18 = -9m

m = -2

Now that we know what m is equal to, we can plug this into our first equation to get an answer for b:

b = -10 - m

b = -10 -(-2)

b = -10 + 2

b = -8

Our final equation is y = -2x - 8

6 0
3 years ago
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