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3 years ago

The angle measures of a triangle are shown in the diagram below

Mathematics

2 answers:

svlad2 [7]3 years ago

4 0

Answer:

x = 12

Step-by-step explanation:

(7x+4)+(2x+5)+(5x+3) = 180

so if you take out the brackets it would be:

7x+4+2x+5+5x+3 = 180

Then you add the similar variables together which would look like:

14x+12=180

Take away 12 from both sides

14x = 180 - 12

14x = 168

Divide 14 from both sides

x = 168/14

x = 12

s344n2d4d5 [400]3 years ago

4 0

Answer:

x=12

Step-by-step explanation:

2x+5+5x+3+7x+4=180

14x+12=180

180-12=168

14x=168

x=12

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tino4ka555 [31]

Answer:

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Step-by-step explanation:

1 x 4 =4

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2 years ago

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Aleksandr [31]

Answer: Your answer should be 21 I believe.

Step-by-step explanation:

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3 years ago

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When a number is a multiple of 6 what are the possible values for the ones digit

Andreas93 [3]

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3 years ago

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Santo paid $16.25 to buy 5 children tickets and 1 adult ticket. Hulda paid $24.00 to buy 4 children tickets and 3 adult tickets.

jenyasd209 [6]

Answer:

The price of an adult ticket it $5

Step-by-step explanation:

To solve this, we would find the system of equations. We would set up two equations that will represent the situation.

Let c = price per children ticket

Let a = price per adult ticket

Santo:

5c + 1a = 16.25

Hulda:

4c + 3a = 24

5c + 1a = 16.25 -> a = 16.25 - 5c

4c + 3a = 24

4c + 3(16.25 - 5c) = 24

4c + 48.75 - 15c = 24

-11c + 48.75 = 24

-48.75 -48.75

-11c = -24.75

/-11 /-11

c = 2.25

5c + a = 16.25

5(2.25) + a = 16.25

11.25 + a = 16.25

-11.25 -11.25

a = 5

a = $5 , c = $2.25

5 0

3 years ago

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A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago