Answer:
one solution
Step-by-step explanation:
Answer:
meow im a dog
Step-by-step explanation:
Answer:
Step-by-step explanation:
2^0 is less than or equal to 1!, because 1<= 1
if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since
(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0
8, 15, 17
You can do this by using the Pythagorean Theorem and setting the sides equal to
shorter leg = x
longer leg = x + 7
hypotenuse = 2x + 1
Then solve so that one side is equal to zero and use the quadratic formula.
