For this case we have a square whose sides are known and equal to 60 ft.
We want to find the diagonal of the square.
For this, we use the Pythagorean theorem.
We have then:
Answer:
from home to second base it is about:

Answer:
x=4
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
(x+5) *x = 6^2
x^2 +5x = 36
Subtract 36 from each side
x^2 +5x - 36 = 0
Factor
( x-4) (x+9) = 0
Using the zero product property
x-4 = 0 x+9 =0
x = 4 x=-9
Cannot be negative since that is negative length
x=4
I believe this is D. The transitive property
6/2 is the number 6 being divided in half by 2; to figure this out just count your 2 table factors! Shown work:
2 x 2 = 4
2 x 3 = 6!
So 6 divided by 2 (6/2) is just the oppoposite of 2 x 3 = 6