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aleksklad [387]
2 years ago
11

What is Add and Simply 7/4 + 5/6 =

Mathematics
1 answer:
Pani-rosa [81]2 years ago
5 0
Simple, first find a common denominator, 24.

So,

7/4*6= 42/24
and
5/6*6=30/24

Then just add, 

42/24
+
30/24

Making it 72/24.

72/24=3

Thus, your answer is, 3.

You might be interested in
he A water pail in your backyard has a small hole in it. You notice that it has drained a total of 1.5 liters in 4 days. What is
Naddika [18.5K]

Answer:

0.375 liters per day

Step-by-step explanation:

1.5 / 4 = 0.375 liters per day

3 0
2 years ago
Please help with this question!
IgorC [24]

Answer:

QR = 5

Step-by-step explanation:

Since the parallelograms are similar, then the ratios of corresponding sides are equal, that is

\frac{AB}{PQ} = \frac{BC}{QR}, then

\frac{9}{3} = \frac{15}{QR} ( cross- multiply )

9QR = 45 ( divide both sides by 9 )

QR = 5


8 0
3 years ago
ASAPPP!!!! HELP I WILL GIVE 100POINTS AND BRAINLIST Question 9 (Essay Worth 10 points)
Luda [366]

Answer:

Part A)

The <em>x-</em>intercepts are (-1/4, 0) and (4, 0).

Part B)

The vertex is a maximum because the leading coefficient is negative.

The vertex is (1.875, 72.25).

Part C)

We can plot the zeros and the vertex, and connect them with a curve.

Step-by-step explanation:

The function given is:

f(x)=-16x^2+60x+16

Part A)

To find the <em>x-</em>intercepts of the function, set the function equal to 0 and solve for <em>x: </em>

<em />0=-16x^2+60x+16<em />

We can divide both sides by negative four:

0=4x^2-15x-4

Factor:

0=(4x+1)(x-4)

Zero Product Property:

x-4=0\text{ or } 4x+1=0

Solve for each case:

\displaystyle x=-\frac{1}{4}\text{ or }x=4

Hence, our zeros are:

\displaystyle \left(-\frac{1}{4}, 0\right)\text{ and } \left(4, 0\right)

Part B)

Note that the leading coefficient of our function is negative.

So, our function will be concave down.

Hence, our vertex will be the maximum.

The vertex is given by:

\displaystyle \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)

In this case, <em>a </em>= -16, <em>b</em> = 60, and <em>c</em> = 16.

Find the <em>x-</em>coordinate of the vertex:

\displaystyle x=-\frac{(60)}{2(-16)}=\frac{15}{8}=1.875

Substitute this back into the function to find the <em>y-</em>coordinate:

f(1.875)=-16(1.875)^2+60(1.875)+16=72.25

Hence, our vertex is:

(1.875, 72.25)

Part C)

Since we already determined the zeros and the vertex, we can plot the two zeros and the vertex and draw a curve between the three points.

The graph is shown below. Again, to do this by hand, simply plot the three points and connect them with a parabola. If necessary, we can also find the <em>y-</em>intercept.

7 0
2 years ago
For a certain population of men, 8 percent carry a certain genetic trait. For a certain population of women, 0.5 percent carry t
slavikrds [6]

Answer:

C) 150 men and 100 women

D) 200 men and 2000 women

E) 1000 men and 1000 women

Step-by-step explanation:

Hello!

To compare the proportion of people that carry certain genetic trait in men and woman from a certain population two variables of study where determined:

X₁: Number of men that carry the genetic trait.

X₁~Bi(n₁;p₁)

X₂: Number of women that carry the genetic trait.

X₂~Bi(n₂;p₂)

The parameter of interest is the difference between the population proportion of men that carry the genetic trait and the population proportion of women that carry the genetic trait, symbolically: p₁-p₂

To be able to study the difference between the population proportions you have to apply the Central Limit Theorem to approximate the distribution of both sample proportions to normal.

<u><em>Reminder:</em></u>

Be a variable with binomial distribution X~Bi(n;p), if a sample of size n is taken from the population in the study. Then the distribution of the sample proportion tends to the normal distribution with mean p and variance (pq)/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

So for both populations in the study, the sample sizes should be

n₁ ≥ 30

n₂ ≥ 30

Also:

Both samples should be independent and include at least 10 successes and 10 failures.

Both populations should be at least 20 times bigger than the samples. (This last condition is to be assumed because without prior information about the populations is impossible to verify)

  • If everything checks out then (p'₁-p'₂)≈N(p₁-p₂; p(1/n₁+1/n₂))

<u>The options are:</u>

A) 30 men and 30 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 30*0.08= 2.4

Failures: y₁= n₁*q₁= 30*0.92= 27.6

Population 2

Successes: x₂= n₂*p₂= 30*0.5= 15

Failures: y₂= n₂*q₂= 30*0.5= 15

The second condition is not met.

B) 125 men and 20 women

n₁ ≥ 30 but n₂ < 30

Both samples are independent but n₂ is not big enough for the approximation.

C) 150 men and 100 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 150*0.08= 12

Failures: y₁= n₁*q₁= 150*0.92= 138

Population 2

Successes: x₂= n₂*p₂= 100*0.5= 50

Failures: y₂= n₂*q₂= 100*0.5= 50

All conditions are met, an approximation to normal is valid.

D) 200 men and 2000 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 200*0.08= 16

Failures: y₁= n₁*q₁= 200*0.92= 184

Population 2

Successes: x₂= n₂*p₂= 2000*0.5= 1000

Failures: y₂= n₂*q₂= 2000*0.5= 1000

All conditions are met, an approximation to normal is valid.

E) 1000 men and 1000 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 1000*0.08= 80

Failures: y₁= n₁*q₁= 1000*0.92= 920

Population 2

Successes: x₂= n₂*p₂= 1000*0.5= 500

Failures: y₂= n₂*q₂= 1000*0.5= 500

All conditions are met, an approximation to normal is valid.

I hope this helps!

6 0
3 years ago
How many 4/5 cup sugar bowls can be filled from 12 cups of sugar?
prisoha [69]
12 sugar / 4/5 sugar/bowls = 15 bowls. Hope you notice the conversion of units. 
4 0
3 years ago
Read 2 more answers
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