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VARVARA [1.3K]
2 years ago
14

I really need help ASAP! The sum of 8 times a number and 15 is 7 find that number

Mathematics
1 answer:
kirza4 [7]2 years ago
3 0

Answer:

8x+15=7 8x=-8 x =-1

Step-by-step explanation:

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Someone Please Help!!!
shusha [124]

Answer:

Blue fabric (triangles) = 27 m²

Green fabric (square) = 9 m²

Step-by-step explanation:

✔️Blue fabric (triangles) = 4(area of triangular face)

= 4(½*b*h)

b = 3 m

h = 4.5 m

= 4(½*3*4.5)

= 27 m²

✔️Green fabric (square) = area of the square base

= s²

s = 3

Area = 3²

= 9 m²

8 0
2 years ago
When you solve a problem involving money, what can a negative number represent
loris [4]
When you owe money it is a negative because when you earn money you have to pay it back
6 0
3 years ago
Justin needs to earn a score of more than 80 on his next math test to earn a B for the semester. Which inequality shows the grad
zvonat [6]

Answer:

b

Step-by-step explanation:

Justin's score has to be greater than 80. the appropriate inequality sign is >

Note that

> means greater than

< means less than

≥ means greater than or equal to  

≤ less than or equal to  

On the number line, since the score has to be greater than 80, the line would start from 80 and end on 95

> or < is represented by unfilled circle

≤ or ≥  is represented by filled circle

6 0
3 years ago
2 6/8 in simplest form
Vesna [10]

Answer:

2 3/4

Step-by-step explanation:

8 0
3 years ago
What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)
Pepsi [2]

Answer:

Vertical Asymptote:

x=1

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

f(x)=log_3(x-1)

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

x-1=0

we get

x=1

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

\lim_{x \to \infty}  f(x)= \lim_{x \to \infty}log_3(x-1)

\lim_{x \to \infty}  f(x)=log_3(\infty-1)

\lim_{x \to \infty}  f(x)=undefined

so, it does not exist

7 0
3 years ago
Read 2 more answers
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