Answer:
0.6915
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 88, \sigma = 4[/ex]What is the probability that a single car of this model emits more than 86 mg/mi of NOX + NMOG?This is 1 subtracted by the pvalue of Z when X = 86. So[tex]Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=%5Cmu%20%3D%2088%2C%20%5Csigma%20%3D%204%5B%2Fex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3EWhat%20is%20the%20probability%20that%20a%20single%20car%20of%20this%20model%20emits%20more%20than%2086%20mg%2Fmi%20of%20NOX%20%2B%20NMOG%3F%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EThis%20is%201%20subtracted%20by%20the%20pvalue%20of%20Z%20when%20X%20%3D%2086.%20So%3C%2Fp%3E%3Cp%3E%5Btex%5DZ%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)


has a pvalue of 0.3085
1 - 0.3085 = 0.6915
The answer is 0.6915
Answer:
u line ub the decimals and s=do regular subtraction
Step-by-step explanation:
63.3% decrease
49 - 18 = 31
31/49 = 0.63265 x 100
= 63.3 rounded to the nearest tenth of a percent
Answer:
- <u>They can catch up with the bus at 10:40 am.</u>
Explanation:
1. Set the time when Liana and her mother can leave (8:40 am) as t₀ = 0; thus the time of driving for them will be t.
2. The average speed at whic Liana's mother drive: 60 miles/hour
3. Thus, the distance they will have driven will be:
- distance = average speed × time = 60t
4. The time the bus left was 8:00 am, which is 40 minutes before Liana and her mom can leave.
Thus, the time wil have driven when Liana and her mom have driven t hours minutes will be: t + 40 min / 60 min/ hour = t + 2/3
5. The average speed of teh bus is 45 miles / hour
6. The distance the bus will have driven will be:
- distance = average speed × time = 45(t + 2/3)
7. When Liana and her mother catch up with the bus, the distances driven by both of them are equal:
Thus, Liana and her mom can catch up with the bus after 2 hours, since 8:40 am; this is, 10:40 am.