Answer:
(a)


(b)
B. The sample is too small to make judgments about skewness or symmetry.
Step-by-step explanation:
Given:


Solving (a):
First, calculate the difference between the recorded TBBMC for both operators:

The last row which represents the difference between 1 and 2 is calculated using absolute values. So, no negative entry is recorded.
The mean is then calculated as:




Next, calculate the standard deviation (s).
This is calculated using:

So, we have



Solving (b):
Of the given options (A - E), option B is correct because the sample is actually too small
E - 30. From 6 to 9 is increase of 1.5times
Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
Answer:
8
Step-by-step explanation:
b=8
c=2
(8)(2)-(2)^3 = 16-8 =8