Answer:
Step-by-step explanation:
The time in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters is given by this equation.
t = va
We need to find the expression for d in terms of t and a.
As velocity = distance/time
So, the distance d is .
Answer:
Angle CAD is 44 degrees
Angle ACD is 44 degrees
Angle ACB is 136 degrees
Angle ABC is 22 degrees
Explanation:
29. Triangle ADC is an isosceles triangle because it has two equal sides.
If segments AD and DC are congruent, then segment AC is the base and the base angles of an isosceles triangle are equal.
Let x be angle CAD.
Let's go ahead x;
Therefore, measure of angle CAD is 44 degrees.
30. Measure of angle ACD is 44 degrees (Base angles of an isosceles triangle are equal)
31. Let angle ACB be y,
Let's go ahead and find measure of angle ACB;
So measure of angle ACB is 136 degrees.
32. Let angle ABC be z.
Triangle ACB is also an isosceles triangle so the base angles are the same.
Let's go ahead and find z;
So measure of angle ABC is 22 degrees.
Answer:
Step-by-step explanation:
The top number is the power and the bottom of the fraction is the root
22/x=9/100
22*100=9x
2200=9x
2200/9=x
244.4