Answer:
The length of NO is ![14\ ft](https://tex.z-dn.net/?f=14%5C%20ft)
Step-by-step explanation:
step 1
Find the value of x
we know that
The Kite has two pairs of equal-length adjacent (next to each other) sides.
so
The perimeter is equal to
![P=2[MN+NO]](https://tex.z-dn.net/?f=P%3D2%5BMN%2BNO%5D)
![P=80\ ft](https://tex.z-dn.net/?f=P%3D80%5C%20ft)
so
![80=2[MN+NO]](https://tex.z-dn.net/?f=80%3D2%5BMN%2BNO%5D)
![40=[MN+NO]](https://tex.z-dn.net/?f=40%3D%5BMN%2BNO%5D)
substitute the values and solve for x
![40=[(3x+5)+(x-7)]](https://tex.z-dn.net/?f=40%3D%5B%283x%2B5%29%2B%28x-7%29%5D)
![40=[4x-2]](https://tex.z-dn.net/?f=40%3D%5B4x-2%5D)
![4x=42](https://tex.z-dn.net/?f=4x%3D42)
![x=21\ ft](https://tex.z-dn.net/?f=x%3D21%5C%20ft)
step 2
Find the length of NO
![NO=(21-7)=14\ ft](https://tex.z-dn.net/?f=NO%3D%2821-7%29%3D14%5C%20ft)
Answer:
Step-by-step explanation:
Y= -2/5 x -4/1 so the answer is Y=8/5
Well first you take 17 and you then take 14 and 19 and you add that all together and you get 50 then you divide 50 in divide that by 3 and you get 16.6
4 x 300 = 1200
0.58 x 90 = 52.2
1200 + 52.2 = 1252.2
62.5 mg sample will remain after 240 days
Step-by-step explanation:
Given
Half-life = T = 60 days
The formula for calculating the quantity after n half lives is given by:
![N = N_0(\frac{1}{2})^n](https://tex.z-dn.net/?f=N%20%3D%20N_0%28%5Cfrac%7B1%7D%7B2%7D%29%5En)
Here
N is the final amount
N_0 is the initial amount
n is the number of half lives passed
The number of half lives are calculated by dividing the time for which the remaining quantity has to be found by half life
The quantity has to be calculated for 240 days so,
![n = \frac{240}{60}\\n = 4](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B240%7D%7B60%7D%5C%5Cn%20%3D%204)
Given
![N_0 = 1000\ mg](https://tex.z-dn.net/?f=N_0%20%3D%201000%5C%20mg)
Putting the values in the formula
![N = 1000 (\frac{1}{2})^4\\=1000 * \frac{1}{16}\\=\frac{1000}{16}\\=62.5\ mg](https://tex.z-dn.net/?f=N%20%3D%201000%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E4%5C%5C%3D1000%20%2A%20%5Cfrac%7B1%7D%7B16%7D%5C%5C%3D%5Cfrac%7B1000%7D%7B16%7D%5C%5C%3D62.5%5C%20mg)
Hence,
62.5 mg sample will remain after 240 days
Keywords: Half-life, sample
Learn more about half-life at:
#LearnwithBrainly