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malfutka [58]
4 years ago
15

In watermelons, bitter fruit (B) is dominant over sweet fruit (b), and yellow spots (S) are dominant over no spots (s). The gene

s for these two characteristics assort independently. A homozygous plant that has bitter fruit and yellow spots is crossed with a homozygous plant that has sweet fruit and no spots. The F1 are intercrossed to produce the F2. What will be the phenotypic ratio in the F2?

Biology
1 answer:
balu736 [363]4 years ago
3 0

Answer:

9 Bitter and yellow spots

3 Bitter and no spots

3 Sweet and yellow spots

1 sweet and no spots

Explanation:

According to the given question, a homozygous plant with bitter fruit and yellow spots (BBSS) is crossed with a homozygous plant that has sweet fruit and no spots (bbss).

The F1 progeny would have bitter fruits with yellow spots. Crossing the F1 would obtain F2 progeny. As per the cross, the F2 progeny would have phenotypic ratio of 9 Bitter and yellow spots: 3 Bitter and no spots: 3 Sweet and yellow spots: 1 sweet and no spots.

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Explanation:

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Cells in a multicellular organism become specialized for particular tasks and communicate with one another in order to maintain homeostasis. Within the human body these are known as hormone cascades, where several complex steps occur- the tissues signal to one another with the use of hormones released by the endocrine system. The regulation (increase and decrease) of these secretions is achieved by negative feedback loops, where the release of certain substances during a cascade in turn halts the secretion of hormones at earlier stages.

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