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oksano4ka [1.4K]
3 years ago
6

Please, Answer Thank you!

Mathematics
1 answer:
bixtya [17]3 years ago
8 0

Answer:

B 1 3/4 inches

Step-by-step explanation:

The tallest flower is 8 1/4 inches

The shortest flower is 6 1/2 inches

The difference is

8 1/4 - 6 1/2

Get a common denominator

8 1/4 - 6 1/2*2/2

8 1/4 - 6 2/4

Borrow 1 ( which is equal to 4/4) from the 8

7 +4/4 +1/4 - 6 2/4

7 5/4 - 6 2/4

1 3/4 inches

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Which linear function shows the same relationship as the table below?
shusha [124]

Answer:

C

Step-by-step explanation:

The simplest way to solve this problem is plugging the X value back into each equation. C (y=4x+1) is the only equation that works for each set. You plug in 1 for X, you get 5 for Y. You plug in 4 for X, you get 17 for Y. Etc.

6 0
3 years ago
Find the missing side of the triangle
likoan [24]

the side x is 15

bottom right angle is 31.61 degrees

other angle is 58.39 degrees

6 0
2 years ago
Read 2 more answers
Binomial (x - 6) and trinomial (-2x2 + x + 9) are the factors of which of the
djyliett [7]

Answer:

Option (3)

Step-by-step explanation:

If binomial (x - 6) and trinomial (-2x² + x + 9) are the factors of a polynomial then their multiplication will be equal to the polynomial.

(x - 6)(-2x² + x + 9) = x(-2x² + x + 9) - 6(-2x² + x + 9)

                              = -2x³ + x² + 9x + 12x² - 6x - 54

                              = -2x³ + 13x² + 3x - 54

Therefore, Option (3) will be the correct option.

8 0
3 years ago
How do you integrate arctan(x dx? i think that if you simplify the integral you get:?
Temka [501]
Integration by parts will help here. Letting u=\arctan x and \mathrm dv=\mathrm dx, you end up with \mathrm du=\dfrac{\mathrm dx}{1+x^2} and v=x. Now

\displaystyle\int\arctan x\,\mathrm dx=uv-\int v\,\mathrm du
\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\int\frac x{1+x^2}\,\mathrm dx

For the remaining integral, setting y=1+x^2 gives \dfrac{\mathrm dy}2=x\,\mathrm dx, so

\displaystyle\int\frac x{1+x^2}\,\mathrm dx=\frac12\int\frac{\mathrm dy}y=\frac12\ln|y|+C=\frac12\ln(1+x^2)+C

Putting everything together, you end up with

\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\frac12\ln(1+x^2)+C
6 0
3 years ago
Please help me with this question, thanks.
arlik [135]

Answer:

  2.48×10^13 miles

Step-by-step explanation:

There are about (365.25 days)(86400 seconds/day) = 31,557,600 seconds in one year. There are 1609.344 meters in one mile. So, the conversion can be written as ...

  (4.22 ly) (3×10^8 m/s) (3.15576×10^7 s/yr) / (1.609344×10^3 m/mi)

  = 4.22×3×3.15576/1.609344×10^(8+7-3) mi

  ≈ 24.8×10^12 mi

4.22 light years is about 2.48×10^13 miles

8 0
3 years ago
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