Question

This box has the same length , width, and height as the 2 basketballs. Which expression gives the volume of the empty space encircling the basketballs inside the box?

Answer 1

Don't you just grab the volume of the box and subtract the volume of the basketballs.

Answer 2

Answer:

$4,608(6- \pi)\ cm^{3}$

Step-by-step explanation:

we know that

The volume of the empty space encircling the basketballs inside the box is equal to the volume of the box minus the volume of the two basketball inside the box

so

The volume of the box is equal to

$V=LWH$

in this problem we have

$L=2*24=48\ cm$

$W=24\ cm$

$H=24\ cm$

substitute

$V=48*24*24=27,648\ cm^{3}$

The volume of the two basketball inside the box is equal to

$V=2*\frac{4}{3} \pi r^{3}$

n this problem we have

$r=24/2=12\ cm$

substitute

$V=\frac{8}{3} \pi 12^{3}$

$V=4,608 \pi\ cm^{3}$

The expression is equal to

$(27,648-4,608 \pi)\ cm^{3}$

$4,608(6- \pi)\ cm^{3}$