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natali 33 [55]
3 years ago
5

Julie is doing an experiment. She is studying a cell that triples every hour. She started the experiment with 24 cells. How many

cells are there at the end of 4 hours?
Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0
I think the answer would be 288, i hope this helps 
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The distance from a point to a line is the length of the ____________ segment from the point to the line.
solniwko [45]

Answer: 1) Perpendicular

2) Concurrent

Step-by-step explanation:

The distance from a point to a line is the length of the perpendicular segment from the point to the line.

As Perpendicular segment is the shortest distance to the point of the line.

When three or more lines intersect at one point, they are concurrent.

Because Concurrent is a situation when three or more lines intersect each other at a single point.

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A bag contains 10 red balls, 5 blue balls and 7 green balls. Find the probability of selecting at random
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Answer:

Probably red ball because it has higher amount

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Write this polynomial expression in its simplest form. Show your work.
Zanzabum

Step-by-step explanation:

(3x² + 4x - 8) - (-2x² + 4x + 2)

[3 - (-2) = 5] , [ 4 - 4 = 0] , [ (-8) - 2 = -10]

5x² + 0x - 10

(or)

5x² - 10

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Write the equation of a line ( slope intercept form y = mx + b)
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y=1/4x-1

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3 years ago
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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