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Dahasolnce [82]

3 years ago

10

We know that a token costs $1.75. If you purchase 10 tokens, you get 2 free tokens. Write and solve an equation to find the appr

oximate reduced price of each token.

1 answer:

Bad White [126]3 years ago

3 0

Answer:

c=(10)($1.75)/12

c=$17.50/12

c=$1.458 which rounds to $1.46 per token

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Dominique works in sales and gets paid $275 per week plus commission. This week he received a total pay of $5075. If his total s

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Answer: Bruh

Step-by-step explanation: is that u ratty ;-;

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2 years ago

Nikhil, Davina and Sid share a tin of celebrations amongst themselves in the ratio of 8:12:20 respectively.

Sav [38]

Answer:

160

Step-by-step explanation:

n : d : s

8 : 12 : 20

davina = 48 sweets

48/12 = 4

8 + 12 + 20 = 40

40 x 4 = 160 sweets total

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2 years ago

On a map, the scale shown is 1 inch : 3 miles. If an island is 0.5 square inches on the map, what is the actual area of the isla

gtnhenbr [62]

Answer:

4.5

Step-by-step explanation:

First we need to turn the ratio of 1 : 3 into a fraction

1:3 = 1/3

Next we need to square that fraction

1 x 1 = 1

3 x 3 = 9

Then we turn those numbers into a fraction

1/9

We turn the .5 into a fraction

.5/x

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1/9 x .5/x

1 x X = X

9 x .5 = 4.5

So

4.5 = X

4 0

3 years ago

3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu

djverab [1.8K]

Answer:

Probability distribution for x:

$P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\$

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

$P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}$

So, we have this probabilty distribution for x:

$P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\$

7 0

3 years ago

You have P = 472 feet of fencing to enclose a rectangular plot that borders on a river. If you do not fence the side along the r

Ray Of Light [21]

The width would be 236 and the lengths would be 118

Use the equations 2L+W=472 and W*L=MAX
Change the first equation to W=472-2L and plug this into the other equation
(472-2L)(L)=MAX
472L-2L^2=M (take derivative)
472-4L=0 (set to 0 to find the max value)
4L=472
L=118
Plug into original to get W=236

Hope this helps!

4 0

2 years ago