All categories

3 years ago

What is 78/500 simplify down to?

Mathematics

2 answers:

vredina [299]3 years ago

8 0

I think its 0.156 because / means division

AlexFokin [52]3 years ago

6 0

2 can into 78 and 500 equally so well divide 78 and 500 by 2.

78/2 = 39
500/2=250
It can't be simplified any more so the answer is 39/250

You might be interested in

Suppose you have the following recursion formula a1 = 1, a2 = 2, and an = a(n - 1)+ a(n - 2)for integers n ≥ 3. How would you de

julia-pushkina [17]

A3=3
a4=5
a5=8

This sequence has properties similar to those of the Fibonacci sequence.

8 0

3 years ago

The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th

choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

$f_x(x) = \dfrac{1}{1500} ; o \le x \le \ 1500$

The function of the insurance is:

$I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \ \ \ \ 250 \le x \le 1500}} \right.$

Hence, the variance of the insurance can also be an account forum.

$Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2$

here;

$E[I(x)] = \int f_x(x) I (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}$

$\dfrac{5}{12} \times 1250$

Similarly;

$E[I^2(x)] = \int f_x(x) I^2 (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}$

$\dfrac{5}{18} \times 1250^2$

∴

$Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]$

Finally, the standard deviation of the insurance payment is:

$= \sqrt{Var(I(x))}$

$= 1250 \sqrt{\dfrac{5}{48}}$

≅ 404

4 0

2 years ago

What is 4/3 divided by 5

Ivanshal [37]

Answer:

4 over 15 is the answer ....

7 0

2 years ago

I need help and I’m like really confused lol❤️

grandymaker [24]

If I did this right it should be 8.

8 0

3 years ago

Read 2 more answers

A grill at a barbecue restaurant will be used to cook sausage links that are 2 lb each and briskets that are 6 lb each. No more

horrorfan [7]

Answer:

2x + 6y ≤ 120

Step-by-step explanation:

From the above question, we are told that: No more than 120 lb of sausage links and briskets will be cooked on the grill.

Let

x = Number of sausage links

y = Number of Briskets

The word NO MORE THAN means less than or equal to 120 lb and this word is represented by the inequality sign:

≤

Sausage links = 2 lb each

Briskets = 6 lb each

The inequality =

2lb × x + 6lb × y ≤ 120lb

2x + 6y ≤ 120

Therefore, the inequality represents all possible combinations of x, the number of sausage links that will be cooked on the grill, and y, the number of briskets that will also be cooked is given as:

2x + 6y ≤ 120

3 0

3 years ago