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Murrr4er [49]
3 years ago
11

If the slope of a line and a point on the line are​ known, the equation of the line can be found using the​ slope-intercept form

, ymxb. To do​ so, substitute the value of the slope and the values of x and y using the coordinates of the given​ point, then determine the value of b. Using the above​ technique, find the equation of the line containing the points (-3,19) and (6,-2)
Mathematics
1 answer:
Natali5045456 [20]3 years ago
4 0

Answer:

<u> 2y + 3x = 3</u>

Step-by-step explanation:

The standard form of equation of a line is expressed as;

y = mx+c

m is the slope

b is the intercept

We are to find the equation of a line passing through the points  (-3,19) and (6,-2)

First get the slope

m = y2-y1/x2-x1

m = -2-19/6-(-3)

m = -21/9

m = -7/3

Get the y- intercept b;

Substitute the coordinate (6, -2) and m = -7/3 into the expression y = mx+b and get b;

-2 = -7/3(6) + c

-2 = -7/2 + c

c = 7/2 - 2

c = (7-4)/2

c = 3/2

Substitute the slope and intercept into the formula

y = mx+b

y = -7x/2 + 3/2

Multiply through by 2;

2y = -7x + 3

2y + 7x = 3

Hence the required equation is<u> 2y + 7x = 3</u>

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\qquad\qquad\huge\underline{{\sf Answer}}♨

Here's the solution :

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kotykmax [81]

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 Pull out like factors :

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Factoring  4x2+8x-9  

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The last term, "the constant", is  -9  

Step-1 : Multiply the coefficient of the first term by the constant   4 • -9 = -36  

Step-2 : Find two factors of  -36  whose sum equals the coefficient of the middle term, which is   8 .

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     -9    +    4    =    -5  

     -6    +    6    =    0  

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     -2    +    18    =    16  

     -1    +    36    =    35

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