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kap26 [50]
2 years ago
6

3. The total cost for 9 bracelets, including shipping was $72. The shipping charge was $9. Define your variable and write an equ

ation that models the cost of each bracelet.
4. Use the equation you have written above determine the cost for each bracelet. Show the algebraic steps that it takes to find the answer. Provide your conclusion.
Mathematics
1 answer:
ikadub [295]2 years ago
8 0

Answer:

The equation that models the cost of each bracelet is 72=9x+9. Cost of each bracelet is $7.

Step-by-step explanation:

Let the cost of each bracelet is defined by the variable x.

Cost of 9 bracelet is 9x. The shipping cost is $9. Therefore the total cost of 9 bracelets, including shipping is

\text{Total Cost}=9x+9

The total cost for 9 bracelets, including shipping is $72.

72=9x+9

Subtract 9 from both sides

72-9=9x+9-9

63=9x

Divide both sides by 9.

7=x

Therefore the cost of each bracelet without shipping changes is $7.

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Two weeks ago the cost to fly was 210 now it is 300 what is the percent increase. What would be the percent increase if the airl
Lunna [17]

Answer:

42.86%    and          61.91%

Step-by-step explanation:

90/210=9/21=42.86%

130/210=13/21=61.91%

8 0
2 years ago
Janine wants a necklace 21 beads long how many blue beads and how many black beads
Kipish [7]
She needs 11 blue beads and 11 black beads
3 0
3 years ago
In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

3 0
2 years ago
In a model of a ship,the mast is 9cm high,while the mast of the actual ship is 12m high.if the length of the ship is 28m,how lon
grandymaker [24]

Answer:

21cm

Step by step:

Scale : 9cm :12m

Therefore 1m = 9/12 cm

28m= 9/12 *28 = <u>21 cm</u>

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%3D%20%5Cfrac%7Bx%20-%204%7D%7B3%7D" id="TexFormula1" title="\frac{5}{
valentina_108 [34]

Step-by-step explanation:

\frac{5}{2}  =  \frac{x - 4}{3}

3 \times \frac{5}{2}  =  \frac{x - 4}{3}

\frac{3}{1}  \times  \frac{5}{2}  =  \frac{x - 4}{3}

cross multiplication

\frac{6 \times 5}{2}  =  \frac{x - 4}{3}

15 =  \frac{x - 4}{3}

15 \times 3 = x - 4

45 + 4 = x

49 = x

4 0
3 years ago
Read 2 more answers
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