The area of a pentagon is found through the following formula:
![A = \frac{1}{4} \sqrt{5(5+2 \sqrt{5}) } * s^{2}](https://tex.z-dn.net/?f=A%20%3D%20%20%5Cfrac%7B1%7D%7B4%7D%20%20%5Csqrt%7B5%285%2B2%20%5Csqrt%7B5%7D%29%20%7D%20%2A%20s%5E%7B2%7D%20)
s is equal to the side length.
Plug 12 and 28 into the formula.
A(12) = 247.75
A(28) = 1348.85
Divide the first result by the second result.
![\frac{247.75}{1348.85}](https://tex.z-dn.net/?f=%20%5Cfrac%7B247.75%7D%7B1348.85%7D%20)
≈
![0.1836](https://tex.z-dn.net/?f=0.1836)
9/49 is equal to this decimal.
The answer is
9/49.
Answer:
![\large\boxed{7x^2-15x+5-2x-8x^2=-x^2-17x+5}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B7x%5E2-15x%2B5-2x-8x%5E2%3D-x%5E2-17x%2B5%7D)
Step-by-step explanation:
![7x^2-15x+5-2x-8x^2\qquad\text{combine like terms}\\\\=(7x^2-8x^2)+(-15x-2x)+5\\\\=-x^2-17x+5](https://tex.z-dn.net/?f=7x%5E2-15x%2B5-2x-8x%5E2%5Cqquad%5Ctext%7Bcombine%20like%20terms%7D%5C%5C%5C%5C%3D%287x%5E2-8x%5E2%29%2B%28-15x-2x%29%2B5%5C%5C%5C%5C%3D-x%5E2-17x%2B5)
Given:
Sum of two consecutive integers is 325.
To find:
The number that is the least of the two consecutive integers.
Solution:
Let the two consecutive integers are x and x+1. So,
![x+(x+1)=325](https://tex.z-dn.net/?f=x%2B%28x%2B1%29%3D325)
![2x+1=325](https://tex.z-dn.net/?f=2x%2B1%3D325)
Subtract 1 from both sides.
![2x=324](https://tex.z-dn.net/?f=2x%3D324)
Divide both sides by 2.
![x=\dfrac{324}{2}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B324%7D%7B2%7D)
![x=162](https://tex.z-dn.net/?f=x%3D162)
The second integer is
![x+1=162+1=163](https://tex.z-dn.net/?f=x%2B1%3D162%2B1%3D163)
Since
, therefore, the least of the two consecutive integers is 162.
This can be represented by ![\boxed{10(x+y)}](https://tex.z-dn.net/?f=%5Cboxed%7B10%28x%2By%29%7D)