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Alex
3 years ago
6

Which set of numbers could represent the lengths of the sides of a right triangle?

Mathematics
2 answers:
monitta3 years ago
7 0
I believe that the answer is the first one
pishuonlain [190]3 years ago
5 0
6,9,11
i had this on a test before hope this helps

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Find the values of a and b such that x^2-x+5=(x-a)^2+b
Romashka [77]

Answer:

a = 0.5 or 1/2

b = 19/4 or 4.75

Step-by-step explanation:

Step 1: Isolate <em>x</em>'s

x² - x = -5

Step 2: Complete the Square

x² - x + 1/4 = -5 + 1/4

(x - 1/2)² = -19/4

Step 3: Move everything to one side

(x - 0.5)² + 4.75

5 0
3 years ago
PLEASE HELP FAST!!!!
Nana76 [90]
For this case what we should do is use the given equation:
 F = mg sin (theta)
 And replace the following values:
 m = 0.01 kg
 g = 9.8m / s ^ 2
 theta = 22.5 degrees
 Substituting we have:
 F = (0.01) * (9.8) * sin (22.5)
 F = 0.037502976 N
 Answer:
 
The force pulling on the pendulum when it makes a 22.5 degree angle with the vertical is:
 F = 0.037502976 N
8 0
3 years ago
What is the answer to 7+4p-6
katovenus [111]


1+4p

the answer cant be simplified any further than this.

4 0
3 years ago
Read 2 more answers
If men's heights are normally distributed with mean 68 and standard deviation 3.1 inches, and women's heights are normally distr
stira [4]

Answer:

the probability that the woman is taller than the man is  0.1423

Step-by-step explanation:

Given that :

the men's heights are normally distributed with mean \mu  68

standard deviation \sigma   = 3.1

And

the women's heights are normally distributed with mean \mu  65

standard deviation \sigma   = 2.8

We are to find the probability that the woman is taller than the man.

For woman now:

mean  \mu = 65

standard deviation \sigma = 2.8

P(x > 68 ) = 1 - p( x< 68)

\\ 1 -p  \ P[(x - \mu ) / \sigma < (68-25)/ 2.8]

= 1-P (z , 1.07)

Using z table,

= 1 - 0.8577

= 0.1423

Thus, the probability that the woman is taller than the man is  0.1423

6 0
3 years ago
An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan
AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=x_{0}]

In this case 95% prediction interval for Y/X=0.5

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

I hope it helps!

6 0
3 years ago
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