Hello!

Recall that:
is equal to
. Therefore:
![\sqrt[3]{x^{2} } = x^{\frac{2}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%20%7D%20%3D%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:

Answer:
h = b - 11.50
Step-by-step explanation:
Sharron(h) has 11.50 less than Rita(b)
h = b - 11.50
1/3^-2
You flip the denominator and the numerator to make the 3^-2 positive.
3^2/1= 3^2= 9
1/2^-3
2^3/1= 2^3= 8
I can already tell you that the negative exponents are not going to be as high in value.
3^-2= 1/3^2= 1/9
2^-3= 1/2^3= 1/8
1/3^-2 (the first option) <=== the highest in value
I hope this helps!
~kaikers
One car 1c
six bicycles 6b
two motorcycles
1c+6b+2m=9cbm
I think this is right but its been forever since i had to do these so
Answer:x^3+13x^2+3
Step-by-step explanation:
(2x^3+11x^2+5)-(x^3-2x^2+2)
Clearing brackets
2x^3+11x^2+5-x^3+2x^2-2
Collect like terms
2x^3-x^3+11x^2+2x^2+5-2
x^3+13x^2+3