Answer:
x = 66.74715005725
Step-by-step explanation:
First you bring over the added variable. 0.194185, and subtract it from 66. Then you divide your difference by 0.985897. This gives you 66.74715005725
Answer:
(-19, 55)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -3x - 2
5x + 2y = 15
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 5x + 2(-3x - 2) = 15
- Distribute 2: 5x - 6x - 4 = 15
- Combine like terms: -x - 4 = 15
- Isolate <em>x</em> term: -x = 19
- Isolate <em>x</em>: x = -19
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -3x - 2
- Substitute in <em>x</em>: y = -3(-19) - 2
- Multiply: y = 57 - 2
- Subtract: y = 55
Answer - 4 classes
117 ÷ 29 = 4.03...
That is the answer. hope this helps.
Answer:
A two-digit number can be written as:
a*10 + b*1
Where a and b are single-digit numbers, and a ≠ 0.
We know that:
"The sum of a two-digit number and the number obtained by interchanging the digits is 132."
then:
a*10 + b*1 + (b*10 + a*1) = 132
And we also know that the digits differ by 2.
then:
a = b + 2
or
a = b - 2
So let's solve this:
We start with the equation:
a*10 + b*1 + (b*10 + a*1) = 132
(a*10 + a) + (b*10 + b) = 132
a*11 + b*11 = 132
(a + b)*11 = 132
(a + b) = 132/11 = 12
Then:
a + b = 12
And remember that:
a = b + 2
or
a = b - 2
Then if we select the first one, we get:
a + b = 12
(b + 2) + b = 12
2*b + 2 = 12
2*b = 12 -2 = 10
b = 10/2 = 5
b = 5
then a = b + 2= 5 + 2 = 7
The number is 75.
And if we selected:
a = b - 2, we would get the number 57.
Both are valid solutions because we are changing the order of the digits, so is the same:
75 + 57
than
57 + 75.
Answer: wait I was wrong I saw thinking about something else
yes that is a unit rate.
