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swat32
4 years ago
10

How do you solve the system of equations for y=2x-4 y=4x-10?

Mathematics
1 answer:
SVEN [57.7K]4 years ago
8 0
Set the equal to each other

2x-4=4x-10
6=2x
x=3
y=2(3)-4
  =6-4
y =2
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What is 5(n- 1/10) = 1/2
Olegator [25]

Answer:

1/5

Step-by-step explanation:

In order to find the answer, we need to isolate the "n."

Get 5 to the other side by dividing both sides by 5

(n-1/10)= 1/2 ÷(5)

Multiply the 2 and the 5 of the equation.

(n-1/10)= 1/10

Next, move the fraction on the left side, to the right.

n= 2/10

Reduce.

n= 1/5

5 0
3 years ago
When using the Distance Formula, the solution is the perimeter of a polygon.<br> true or false?
natali 33 [55]

Answer:

false

Step-by-step explanation:

When solving the distance formula it is the distance from one point to another. If you had a rectangle and used the distance formula from each point then you would have a perimeter

5 0
3 years ago
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Papessa [141]

Answer:

Ali´s secret number is 13

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
2x + 3y = 3 and x + 6y = -3
jekas [21]

Answer:

Step-by-step explanation:

Multiplying x+6y=-3 with 2 so its equal to first eqn,

Eliminating,

2x + 3y = 3        (1)

2x +12y = -6       (2)                  (because subtracting)

------------------

      -9y =9

     ∴y=-1

eq. y in 1

2x -3=3

2x=3+3

x=6/2

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4 0
3 years ago
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
3 years ago
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