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andriy [413]
3 years ago
13

The percentage profit earned by selling a watch for Nu 1920 is equal to the percent loss incurred by selling the same watch for

Nu 1280. At what price should the watch be sold to make 25% profit​
Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

Answer:

2,000

Step-by-step explanation:

The computation of the price that should be sold for making 25% profit is shown below:

Let cost price be x

Now the equation would be

(1,920 - x) ÷ x × 100 = (x - 1,280) ÷ x × 100

1,920 - x = x - 1,280

2x = 3,200

x = 1,600

Now the sale price would be

= 1,600 × 1.25

= 2,000

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Step-by-step explanation:

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Simplify y+1<3 please need help
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STEP-BY-STEP SOLUTION:

Let's first establish the inequality which we need to solve as displayed below:

y + 1 < 3

To begin with, we need to make ( y ) the subject by keeping it on the left-hand side of the inequality and placing all other numbers on the right-hand side of the equality as displayed below:

y + 1 < 3

y < 3 - 1

Then, we simply simplify / solve as displayed below:

y < 3 - 1

y < 2

ANSWER:

y < 2
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Step-by-step explanation:

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A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

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4 years ago
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