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3 years ago

Which is the best description of a computer virus?

Computers and Technology

2 answers:

solniwko [45]3 years ago

8 0

Answer:

a program that can damage a computer

Explanation:

MatroZZZ [7]3 years ago

6 0

The best description of a computer virus is. Someone first starts out making a malicious program, then can send it to a unexpected user. After that, when the user opens the malicious program, it can do negative things on the target. The virus first starts out in the system32, then infects a random file type for example, exe files, or dlls etc. Then random errors can pop up on the computer saying "YOUR COMPUTER IS UNDER RISK! CALL THIS NUMBER NOW! 555-555-5555" and the options of the error, can direct you to a website, that can give you another virus. To get rid of a virus, you have to ignore the popups that comes onto your computer, and get a strong antivirus like avast, or avg. Then let it scan the system. After when the scan is done, it will show up the virus, and it will give you options "to delete virus or ignore it" you would hit delete. I hope this answer helped you. Let me know if you have any more questions! Thanks!

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Given a floating-point formal with a k-bit exponent and an n-bit (fraction, write formulas for the exponent E, significant M, th

ANEK [815]

Answer:

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112 ≈ 7/4

fractional value ( F ) = 0.112

And, numeric value of the quantity ( V ) = 7

The exponent bits will be represented as : 100----01.

while The fraction bits will be represented as : 1100---0.

B) The largest odd integer that can be represented exactly

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

= 1.11------12 = 2 - 2-n

also the fractional value ( F ) =

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits will be represented as follows: n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

C) The reciprocal of the smallest positive normalized value

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E ) = 2k-1 – 2

While the significand value ( M ) = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

Explanation:

E = integer value of exponent

M = significand value

F = fractional value

V = numeric value of quantity

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112 ≈ 7/4

fractional value ( F ) = 0.112

And, numeric value of the quantity ( V ) = 7

The exponent bits will be represented as : 100----01.

while The fraction bits will be represented as : 1100---0.

B) The largest odd integer that can be represented exactly

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

= 1.11------12 = 2 - 2-n

also the fractional value ( F ) =

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits will be represented as follows: n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

C) The reciprocal of the smallest positive normalized value

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E ) = 2k-1 – 2

While the significand value ( M ) = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

8 0

3 years ago

Implement a function named largerThanN that accepts three arguments: an array of type int, the size of the array of type int and

levacccp [35]

Answer:

import java.util.Scanner;

public class NewArray {

//Main Method begins here

public static void main(String[] args) {

int [] numbers = {30,20,50,2,-1,44,3,12,90,32}; //The given array

Scanner in = new Scanner(System.in);

System.out.println("enter a number");

int n = in.nextInt(); //Receive the number from the user

//Calling the method largerThanN

largerThanN(numbers, numbers.length,n);

}

//The method largerThanN begins here

public static void largerThanN(int []intArray, int arraySize, int n){

for(int i = 0; i < intArray.length; i++){

if(intArray[i] > n){

System.out.println(intArray[i]);

}

Explanation:

Uisng the Java prograamming language the solution is provided above.

Please see the comments within the code for detailed explanation

The key logic within the method largerThanN () is using a for loop to iterate the entire array. Within the for loop use an if statement to compare each element with the the number n entered by the user

6 0

3 years ago

Amy wants to controls the overall process of creating digital designs. Which career is Amy pursuing?

Hoochie [10]

Game designer

I hope this helped

8 0

4 years ago

Can someone please answer this? It isn't Insert

enyata [817]

Answer:

The answer for this question is b Add to

3 0

3 years ago

Why is spyware more dangerous than adware

steposvetlana [31]

To find out how spyware is more dangerous, we must know what each term mean.

Adware is a software that automatically displays advertising material usually on a site that a user goes to.

Spyware is a unwanted software that steals your internet usage data and personal information.

So while Adware can be extremely annoying, it is not as potentially harmful as Spyware, which can steal your personal information and potentially ruin your life.

7 0

3 years ago