.0000458 put this in scientific notation

Determine if the shape shown is a triangel squear rectangel or hexagon or other

jonny [76]

You can determine the shape if it is a triangle, square, rectangle, or hexagon (or other) by seeing how many sides it has.
a triangle has 3 sides.
a square has 4 sides.
a rectangle also has 4 sides.
a pentagon has 5 sides.
a hexagon has 6 sides.

8 0

2 years ago

a box of chocolate contains 5 milk chocolate dark chocolate and 5 white chocolate you randomly selecting III chocolates the firs

nordsb [41]

Answer:

independent

Step-by-step explanation:

because each chocolate was a different flavor

5 0

3 years ago

Estimate by rounding both numbers to tens and then multiplying.<br> 22 x 47 is approximately

Diano4ka-milaya [45]

Answer:

the answer is 1060

Step-by-step explanation:

1064 rounded by tens is 1064

8 0

3 years ago

Read 2 more answers

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$

The minimum cost occurs at the point where the derivative equals zero.

$C^{'}=\frac{-27840+32\pi r^3}{3r^2}$

$When \:C^{'}=0$

$-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518$

Recall:

$h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet$

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0

2 years ago

write an equation of the line that's passes through the point (1,6) and is parallel to the line whose equation is y= 3x - 5

Alex Ar [27]

Parallel lines have the same slope.
so to find any line, you need a set of points, and a slope.
we already have the slope, being 3.
so, use the equation
y- (y-point)/ x-(x-point)=slope.
y-6. 3
---- = ---- (make it a fraction by puttingitover 1)
x-1. 1
cross multiply.
1(y-6)=3 (x-1)
y-6=3x-3
add 6 to both sides
Final answer: Y=3x+3

7 0

2 years ago