The ship movement is an illustration of distance and bearing
The ship is 31.97 miles from its point of departure
<h3>The distance from the point of departure?</h3>
The given parameters are:
- Distance east = 40 milies
- Distance southwards = 70 miles
- Angle = 12 degrees
See attachment for the image of the above parameters
The distance (x) from the point of departure is then calculated using the following cosine function
a^2 = b^2 + c^2 - 2bc * cos(Ф)
So, we have:
x^2 = 40^2 + 70^2 - 2 * 40 * 70 * cos(12)
Evaluate the exponent and the product
x^2 = 6500 - 5477.63
Evaluate the difference
x^2 = 1022.37
Evaluate the exponent
x = 31.97
Hence, the ship is 31.97 miles from its point of departure
Read more about distance and bearing at:
brainly.com/question/24142612
Answer:
I say A or B but in favor A
Step-by-step explanation:
Answer:
11.45 lumens
Step-by-step explanation:
We are given that

Where x=Depth
I=Intensity of light
We have to find the intensity of the light at a depth of 20 feet.
Substitute the value of x





Hence, the intensity of the light (in lumens) at a depth of 20 feet=11.45 lumens
Answer:
f(1/3) = 9
Step-by-step explanation:
f(x)=1/x+2/x
Combine terms
f(x) = 3/x
f(1/3) = 3 / (1/3)
f(1/3) = 9
Well 40 times 6 is 240 which means that you don't have to round.