Answer:
P(A U B)= 0.08
Step-by-step explanation:
1.Let:
P(A) as the probability that a psiton has an under-fill defect
P(B) as the probability that a pistón has a porosity defect
P(A ∩ B) the probability of having both defectos
Then:
P(A)=0.05
P(B)=0.04
P(A ∩ B)=0.01
2. The probability that a randomly chosen piston has a defect could be calcularse as the union of the probability of choosing a piston with am under-fill defect and one with porosity defect.
That Is P(A U B)
Aplying the probability properties we have:
P(A U B)= P(A) + P(B) -P(A ∩ B)
Replacing the probabilities:
P(A U B)= 0.05+0.04-0.01
P(A U B)= 0.08
Answer:76
Step-by-step explanation:
Answer:
I think it's 1 fourth or .25
Step-by-step explanation:
6m-3k²
= 6(7) - 3 (2)²
= 42 - 3(4)
= 42 - 12
= 30
m + | 2m-k|
7 + | 2(7) - 2|
7 + | 14-2|
7 + 12
= 19
45% of 900 kg is 405 kilograms