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Scorpion4ik [409]

2 years ago

12

Julia writes 2fractions with the same denominator that have numerators 5and 7.What could the denominator be if the sum is less t

han 1? Equal1?Greater than 1?

1 answer:

Goshia [24]2 years ago

8 0

Answer:

Less then denominator can be 20. I don't know equal. Greater denominator can just be 1.

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What is 0.25 (repeating 5) as a fraction?

Vanyuwa [196]

1/2 or 2/4 pretty sure

4 0

2 years ago

The Quadratic Equation c² + 6c+ 8 = 0<br><br> Show work please

Bad White [126]

The formula for the quadratic formula is x (c in this case) = (-b(+/-)√(b²-4ac))/2a
This is used for an equation in standard quadratic form: ax² + bx + c = 0
1.) Put it in the correct form, if not already in it.
Ex. c² + 6c + 8 = 0
2.) Identify each part of the equation:
a = 1 (the leading coefficient), b = 6 (the coefficient in front of the second variable), c = 8
3.) Plug in each variable answer
c = (-6(+/-)√(6²-4(1)(8))/2(1)
4.) Simplify
c = (-6(+/-)√(36-(4*8))/2
c = (-6(+/-)√(36-32))/2
c = (-6(+/-)√(4))/2
c = (-6(+/-)2)/2
*Here, the equation splits in two. It becomes:
c = (-6+2)/2 AND c = (-6-2)/2
*Simplify again:
c = -4/2 AND c = -8/2
c = -2 AND c = -4
The answers c = -2 and c = -4 would solve the given equation.
Hope this helps! :)

6 0

3 years ago

Read 2 more answers

Two similar prisms have heights 4 cm and 10cm what is the ratio of their surface areas

Slav-nsk [51]

Let k be the scale factor relating two similar prisms $P_{1}$ and $P_{2}$ , such that for corresponding parts of prisms $P_{1}$ and $P_{2}$ (for heights, in particular) we have $k= \frac{height\ of \ P_{1} }{height \ of\ P_{2} }$ . In our case $k= \frac{4}{10} = \frac{2}{5}$ .
For surfaces area we have $\frac{Surface \ area \ of \ P_{1} }{Surface \ area \ of \ P_{2}} = k^{2} =( \frac{2}{5} )^{2}= \frac{4}{25}$ .
So, the right answer is 4:25 (choice B)

4 0

3 years ago

PLZ HELP its Triangle Properties and where using the 45º-45º-90º Triangle Theorem and the 30º-60º-90º Triangle Theorem.

den301095 [7]

Answer:

The answer to your questions is below

Step-by-step explanation:

4.-

In a 45°-45°-90° triangle, the length of the legs are "x" and the length of the hypotenuse is x $\sqrt{2}$

Then, in this problem, the length of the leg is 7 then the length of the hypotenuse will be 7 $\sqrt{2}$

5.- In a 30°-60°-90° triangle, the length of the hypotenuse is 2x, the length of the longer leg is x $\sqrt{3}$ and the length of the shorter leg is x.

In this problem we have the length of the hypotenuse = 20 and find x.

2x = 20

x = 20/2

x = 10

longer leg = x $x\sqrt{3} = 10\sqrt{3}$

6.- nonzero

7.- hypotenuse = 20 cm

Find x

2x = 20

x = 20/2

x = 10

Shoter leg = x = 10 cm

4 0

3 years ago

Read 2 more answers

Look at pic 10 pts will mark brainilest

Nina [5.8K]

Answer:

<em>For part one...</em>

<em><u>you will multiply 4.5 by 3 to get 13.5 . </u></em>

<em>For part two,</em>

<u><em> you will multiply 3m by 4 to get 12.</em></u>

<u><em></em></u>

<em> (: </em><em><u>I hope this helps! BRAINLIEST is appreciated to get to virtuoso</u></em><em> :)</em>

6 0

2 years ago