The area of the classroom is 8,671 in squared. you get this by multiplying base x height x width. You plug the same formula into the dollars he mentions and get 0.06890922 in squared. Than you divide the classroom dimensions by the dollar dimentions. that's 8,671 ÷ 0.06890922 = 125,832.21809795. rounding that to one decimal place, it would take $125,832.2 to fill up the classroom. (I might have gotten this wrong but I think this is the answer)
If the base of the tank is a square, then the length and width are the same, making the area length*width*height=length*length*8=length^2*8=1268. Dividing both sides by 8, we get length^2=158.5 and by square rooting both sides we get length=sqrt(158.5)=around 12.6 for the length (and width), and 8 feet for the depth/height
Answer:
2m - 20
Step-by-step explanation:
Given that:
First week minutes = m
Second week minutes = (2 * first week minutes - 20)
Second week = 2m - 20
Therefore, the expression for the number of practice minutes for the second week is :
2m - 20
It all depends upon what other things are given If hypotenuse is not given, in cosine or reciprocals are useless. In that case only tan and cot will be equally convenient if adjacent sides are given.
Answer:
The ans would be 291 (however we can round this off to 290 as no can partially vote as 0.1)
Step-by-step explanation:
We can easily find the loser's vote by-
70% of 969= 678.9
now, all we need to do is find the winners vote
we know that the total no. of votes= 969 & we know the no. of votes loser got
so, subtracting the losers vote from 969 would give us the remaining no. of votes (the winner's votes)....so,
969-678.9=290.1
we can round this off to 290
