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mixer [17]
3 years ago
5

3. A test has 20 questions worth 100 points total. The test consists of True/False questions worth 4 points each and multiple ch

oice questions worth 8 points each
C. Solve the system to determine how many questions of each type there are on the test. You may use any method, but you must show your work.
Mathematics
2 answers:
Aleks [24]3 years ago
7 0

Answer:


x+y=20

4x+8y=100

x=-2y+25

x=-y+20

-2y+25=-y+20

-y=-5

y=5

x=15

There are 15 true/false questions and 5 multiple choice questions



Cerrena [4.2K]3 years ago
3 0
X+y=20
4x+8y=100
x=-2y+25
x=-y+20
-2y+25=-y+20
-y=-5
y=5
x=15
There are 15 true/false questions and 5 multiple choice questions

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A 1460

Step-by-step explanation:

Suppose that it is 185 students multiplied by 14 school districts.

ie 185*14=2590

4050-2590= 1460

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Je ne parle pas français donc j'utilise un traducteur. J'espère qu'il n'y a pas trop d'erreurs. Le frère de Maurice a dépensé 5,20 $ et Maurice 20,80 $

Step-by-step explanation:

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2 years ago
Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure
Marina CMI [18]

Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

4 0
3 years ago
Read 2 more answers
Hello! Can someone pls help me???
qwelly [4]

Answer:

5x+6y=60

Step-by-step explanation:

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If y varies directly with x and y = 3 when x =12, then what is the value of y when x =40?
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Its c 10 and other fillar so i can answer
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3 years ago
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