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posledela
3 years ago
7

Solve for a 6a-15=72

Mathematics
2 answers:
schepotkina [342]3 years ago
8 0

Answer:

14 1/2

Step-by-step explanation:

6a-15=72

+15 on both sides

6a = 87

Divide by 6 on both sides

a = 14 1/2

S_A_V [24]3 years ago
7 0

Answer:

D. 14 1/2

Step-by-step explanation:

First, add 15 to both sides:

6a - 15 = 72

6a = 87

Divide by 6

6a = 87

a = 14.5

Therefore, the answer to your question is D. 14 1/2

<em>Hope this helps!!</em>

<em>- Kay :)</em>

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A sequence is defined by the recursive formula f (n + 1) = f(n) – 2. If f(1) = 18, what is f(5)?​
bekas [8.4K]

Answer:

this question doesn't make sense sorry

7 0
3 years ago
Find the area of a regular pentagon with an apothem of 6 inches and a side length of 8.7 inches. Round to the nearest tenth.
Lapatulllka [165]
  1. The area of the pentagon is 130.5 inches. The area of a pentagon, if you don’t know, is equal to the perimeter of the pentagon times the apothem, all divided by 2. Because one side of the pentagon has a length of 8.7 inches, and all sides of a pentagon have the same length, then the perimeter would be equivalent to 8.7 times 5, which equals a perimeter of 43.5 inches. Now that our perimeter is found, our equation is set (because the apothem is 6 inches, as said in the problem). Now, to solve, we have to multiply the perimeter (43.5 in.) by the apothem (6 in.), which equals 261 inches. Now, all we have to do is divide it by 2, which will give us our answer of 130.5 inches. Bonus: The answer only reaches out to one decimal point, meaning that there is no need to round!
5 0
3 years ago
Paul has three cube-shaped boxes. Each box is a different size
qwelly [4]

Answer:

See explanation

Step-by-step explanation:

Paul has three cube-shaped boxes. Each box is a different size and they are stacked from the largest to the smallest. Some information about the boxes is given below.

  • The combined volume of the three boxes is 1,197 cubic inches.
  • The area of one face of the medium box is 49 square inches.
  • The volume of the smallest box is 218 cubic inches less than the volume of the medium box.

1. The medium box has the area of one face of 49 square inches, then

a^2=49\\ \\a=7\ inches

is the side length.

The volume of the medium box is

a^3=7^3=343\ in^3.

2. The volume of the smallest box is 218 cubic inches less than the volume of the medium box, then the volume of the smallest box is

343-218=125\ in^3.

Ib is the side length, then

b^3=125\\ \\b=5\ inches

The area of one face is

b^2=5^2=25\ in^2.

3. The volume of the largest box is

1,197-343-125=729\ in^3,

then if c is the side length,

c^3=729\\ \\c=9\ inches.

4. The total height of the stack is the sum of all sides lengths:

a+b+c=7+5+9=21\ inches

5. Find the surface area of each box:

  • small 6b^2=6\cdot 5^2=6\cdot 25=150\ in^2;
  • medium 6a^2=6\cdot 7^2=6\cdot 49=294\ in^2;
  • large 6c^2=6\cdot 9^2=6\cdot 81=486\ in^2.

In total, Paul needs

150+294+486=930\ in^2

of wrapping paper. He has 1,000 square inches, so Paul has enough paper to wrap all 3 boxes.

8 0
4 years ago
Stuck on this last problem​
marissa [1.9K]

Answer:

A.

Step-by-step explanation:

Since the associate property is grouping and since the only that groups the number differently is A.

6(1/3 x 7/5) changes to (6 x 1/3) 7/5

Hope this helps :)

4 0
3 years ago
Will give brainiest!!!////
mariarad [96]
Instead of asking and waiting for a long time you can just use google or apps like Socratic or photomath better get brainleist
5 0
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